Hcc-se math 2320: differential equations 120 of f)s+2 42o. determine the inverse lapl a) -e cos(2) c) y(t) = 5l'e-u-e' sin (v21) b) y(t) = 6t5e-21-e" sin(21) d) y(t) = 514e-2,-e, cos(5)

i dont know nkw

step-by-step explanation:

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all it means is function 3

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y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )