Find an equation of the vertical line through (-6, -9) in the form ax+ byc, where a, b, and c are integers with no factor common to all three, and az0. the equation is (type an equation.)

The equation of the vertical line through (-6, -9) is 1x+0y=-6.

Step-by-step explanation:

The standard form of a line is

where a, b, and c are integers with no factor common to all three, and a>0.

If a vertical line passes through the point (a,b), then the equation of vertical line is x=a.

It is given that the vertical line passes through the point (-6,-9). Here a=-6 and b=-9, so the equation of the vertical line through (-6, -9) is

The standard form of the line is 1x+0y=-6. where the value of a,b c are 1, 0, -6 respectively.

Therefore the equation of the vertical line through (-6, -9) is 1x+0y=-6.

answer: idk

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1