Using a long rod that has length m, you are going to lay out a square plot in which the length of each side is m. thus the area of the plot will be m^2. however, you do not know the value of m, so you decide to make n independent measurements x1, x2, … , xn of the length. assume that each xi has mean m (unbiased measurements) and variance s^2.a. show that x bar 2 is not an unbiased estimator for m^2.b. for what value k is the estimator x bar 2 -ks2 unbiased for m^2?

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

i’m sorry but i don’t know sorry

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)