The graph of the equation $x + 2y + 3 = 0$ is perpendicular to the graph of the equation $ax + 2y + 3 = 0$. what is the value of $a$?

a = -4.

Step-by-step explanation:

If the are perpendicular then the slope of one graph will be - 1 / slope of the other.

Convert each equation to slope-intercept form:

x + 2y + 3 = 0

2y = = -x - 3

y = (-1/2)x - 3/2 (Slope/intercept form)

So the slope of the line perpendicular to this  will be - 1 / (-1/2) = 2.

Consider the other line:

ax + 2y + 3 = 0

2y = -ax - 3

y = (-a/2) x - 3/2 (Slope/intercept form)

So the slope for this line    - a/2 and it equals 2.

-a/2 = 2

-a = 2*2 = 4

a = -4 (answer).

35 is an outlier

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm