100 students take a course pass/fail. if they pass they get 4 points towards their gpa, if they fail they get 0. if 90 students pass, what is the mean and standard deviation (to 1 decimal) of the points earned?

mean:

standard deviation: a1

Formulas
Mean = total sum of points / # of data
[Stantard deviation] ^ 2 = {Sum of [every data - mean]^2 } / [number of data - 1]

Procedure:

Mean = total sum of points / # of data

Total sum of points = point of pass + point of fail

points of pass = 90*4 = 360
point of fail = 10*0 = 0
Total sum of points = 360

Number of data = 100

Mean = 360/100 = 3.6

[Stantard deviation] ^ 2 = {Sum of [every data - mean]^2 } / [number of data - 1]

[Sum of every data - mean]^2  = 90*[4 -3.6]^2 + 10* [0 - 3.6]^2 = 14.4 + 129.6 = 144

 [Stantard deviation] ^ 2 = [144]/[100-1] =144/99

Standar deviation = √(144/99) = 1.206

The answer would be d i think but i’m for sure it is not a and c