In a study of cell phone usage and brain hemispheric dominance, an internet survey was e-mailed to 6965 subjects randomly selected from an online group involved with ears. there were 1330 surveys returned. use a 0.01 significance level to test the claim that the return rate is less than 20%. use the p-value method and use the normal distribution as an approximation to the binomial distribution. identify the null hypothesis and alternative hypothesis. a. upper h 0: pequals0.2 upper h 1: pless than0.2 b. upper h 0: pgreater than0.2 upper h 1: pequals0.2 c. upper h 0: pequals0.2 upper h 1: pnot equals0.2 d. upper h 0: pnot equals0.2 upper h 1: pequals0.2 e. upper h 0: pless than0.2 upper h 1: pequals0.2 f. upper h 0: pequals0.2 upper h 1: pgreater than0.2 the test statistic is zequals nothing. (round to two decimal places as needed.) the p-value is nothing. (round to three decimal places as needed.) because the p-value is

i think it is 70

step-by-step explanation:

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

where are the graphs?

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.