How many yards of the fencing materials do they need for the fence ? explain

152.7 yd

Step-by-step explanation:

I presume that there is a fence around the perimeter and separating the various plots.

AG = BF  = CE = 18 yd

GH = DE = 12 yd

EO² = DE² + DO²

1 5² = 12²  + DO²

225 = 144 + DO²

  81 = DO²

DO = 9

BC = DO = EF  = 9 yd

AC = DH =  EG = 17 yd

AO² = AB² + BO² = 8² + 6² = 64 + 36 =100

AO = √100 = 10 yd

CO² = BC² + BO² = 9² + 6² = 81 + 36 = 127

CO = √127 yd

GO² = FG² + FO² = 8² + 12² =64 + 144 = 208

GO = √208 = 4√13 yd

Fencing needed

= (AC + DH + EG) + (AG + BF + CE) + AO +   CO  + EO + GO

=        (3 × 17)        +         3 × 18)       + 10   + √127 + 15  + 4√13

=           51            +            54          + 25   +  11.27 +          14.42  

=       152.7 yd

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.