Circle a has a diameter of 7 inches, a circumference of 21.98 inches, and an area of 38.465 square inches. the diameter of circle b is 6 inches, the circumference is 18.84 inches, and the area is 28.26 square inches.

part a: using the formula for circumference, solve for the value of pi for each circle. (4 points)

part b: use the formula for area and solve for the value of pi for each circle. (4 points)

part c: what observation can you make about the value of pi for circles a and b?

Part A

π * r * 2 = C Formula

π * 3.5 * 2 = 21.98 Replace Circumference and radius

π * 3.5 * 2 / 2 = 21.98 / 2 Get rid of *2 by divide by 2

π * 3.5 = 10.99 Simplify

π * 3.5 / 3.5 = 10.99 / 3.5 Get rid of *3.5 by divide by 3.5

π = 3.14 Simplify

Circle A proves that π is equal to 3.14

π * r * 2 = C Formula

π * 3 * 2 = 18.84 Replace Circumference and Radius

π * 3 * 2 / 2 = 18.84 /2 Get rid of *2 by divide 2

π * 3 = 9.42 Simplify

π * 3 / 3 = 9.42 Get rid of *3 by divide 3

π = 3.14 Simplify

Circle B proves that π is equal to 3.14

Part B:

Circle A

π=

38.465/3.5^2=

38.465/ (3.5 * 3.5)=

38.465/ 12.25 =

3.14

Circle B

π=

28.26/3^2=

28.26/ (3*3)=

28.26/ 9=

3.14

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

rx and sx

step-by-step explanation: