Two automobiles start together from the same place and travel along the same route. the first averages 40 miles
per hour and the second 55 miles per hour. how many miles further along the route is the second car at the end of
5 hours?
make a selection:
a. (55 x 5) - (40 x 5)
b. 55 x 5
c. 55 - 40
d. 55/5 - 40/5
next > >

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

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A. (55 x 5) - (40 x 5)

Step-by-step explanation:

The "speedier" car goes 55 mph * 5 hrs = 55*5 miles

The "slower" car goes 40mph * 5   hrs = 40*5 miles

The distance between them is

55  *5 - 40*5

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

i'm sorry i don't know

step-by-step explanation: