Solve the equation below.

a. x= -2
b. x=0,2
c. x= 2
d. x=0,-2

B. x=0,2

Step-by-step explanation:

(x+4)      1

=

6x          x

Using cross products

x * (x+4) = 1*6x

Distribute

x^2 +4x = 6x

Subtract 6x from each side

x^2 +4x-6x = 6x-6x

x^2 -2x = 0

Factor out an x

x (x-2) = 0

Using the zero product property

x=0  x-2 =0

x=0  x-2+2 =0+2

x =0   x=2

Option C is correct.

Step-by-step explanation:

We need to solve the equation below and find value of x

Cross multiply

x(x+4)=6x

x^2+4x=6x

x^2+4x-6x=0

x^2-2x=0

Taking x common

x(x-2)=0

x=0 and x-2 =0

x=0 and x= 2

Verify solutions

putting x=0

x+4/6(0) = 1/0

the solution is undefined.

Putting x = -2

2+4/6(2) = 1/2

2+4/12 = 1/2

6/12=1/2

1/2=1/2

the solution is defined.

The solutions is x=2 as for x=0 the solution is undefined.

So, Option C is correct.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

answer: idk

step-by-step explanation: