The "favorable outcome" is to get 4 winning numbers and 2 non-winning numbers. how many ways can we get 4 winning numbers out of the 6 possible numbers? how many ways can we get 2 non-winning numbers out of all of the non-winning numbers? if we multiply those numbers together, we will get the favorable outcomes. for total outcomes, we need to see how many ways we can pick our 6 numbers.

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60

Let smaller number be 2x , then the nest even number will be 2x + 2so   2x + 4(2x + 2) = 582x + 8x + 8 = 5810x = 50x = 5  so the first number is 2*5   = 10 and second one is 12