What is the average rate of change for this quadratic function for the interval from
x = 2 to x = 4?

Hence,the average rate of change for this quadratic function for the interval from x = 0 to x = 2 is:

-2

Step-by-step explanation:

The average rate of a function f(x)  from x=a to x=b is given as:

Clearly we are asked to find the average rate of change from x=0 to x=2.

i.e. a=0 and b=2

Also, from the graph it could be observed that:

f(0)=1

and f(2)=-3

Hence, the average rate of change is calculated as:

Hence,the average rate of change for this quadratic function for the interval from x = 0 to x = 2 is:

-2

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

10cm

step-by-step explanation:

ik