Given a -4ax 2ay 3az and b 3ax 4ay az, find a. magnitude of 5a 2b b. a unit vector in the direction of (5a - 2b)/ia c. the vector component of ba that is parallel to b, and d. the vector component of a that is perpendicular to b
|(5 points) a. 31.12 (5 points) b. -0.83a,-0.064ay0.54az (5 points) c. -0.807ax 1.076ay +0.269az (5 points) d. -3.19a, 3.07ay 2.73a

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website:

step-by-step explanation:

yes it represnts a functio, their are not 2 of the same numbers on the both sides