All seasons plumbing has two service trucks that frequently need repair. if the probability the first truck is available is .73, the probability the second truck is available is .59, and the probability that both trucks are available is .43: what is the probability neither truck is available

.11

Step-by-step explanation:

Let F be the event that the first truck is available and S be the event that the second truck is available.

The probability of neither truck being available is expressed as P(∩) , where P() is the probability that the event F doesn't happen and P() is the probability that the event S doesn't happen.

P()= 1-P(F) = 1-0.73 = 0.27

P()=1-P(S) = 1-0.59 = 0.41

Since   and aren't mutually exclusive events, then:

P(∪) = P() + P() - P(∩)

Isolating the probability that interests us:

P(∩)= P() + P()- P(∪)

Where P(∪) = 1 - 0.43 = 0.57

Finally:

P(∩) = 0.27+ 0.41 - 0.57 = 0.11

step-by-step explanation:

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i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.