The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. what is the point-slope form of the equation for this line?

y+13 = 5(x+2)

Step-by-step explanation:

y = 5x-3

The slope is 5 since it is in the form y= mx +b where m is the slope

The point slope form of the equation of a line is

y-y1 = m(x-x1)  where (x1,y1) is the point

y--13 = 5(x--2)

y+13 = 5(x+2)

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step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.