Abox contains 8 white cards and 6 black cards.
what is the probability of choosing a black card then a white card, without replacement?

The probability of choosing a black card then a white card, without

replacement is 24/91

Step-by-step explanation:

* Lets explain how to solve the problem

- There is a box contain some cards

- There are 8 white cards in the box

- There are 6 black cards in the box

- Two cards are choosing from the box a black card and then a white

 card, without replacement

∵ The number of the white cards in the box is 8

∵ The number of the black cards in the box is 6

∴ The total number of the cards in the box = 8 + 6 = 14

- We will chose the first card which is a black card

- We have 6 choices from 14 choices

∵ The number of the black cards is 6

∵ The total number of the cards is 14

∴ P(black) = 6/14 = 3/7

- Now the number of the black cards is 5 and the total number of the

 cards is 13 because there is no replacement

- We will chose the second card which is a white card

- We have 8 choices from 13 choices

∵ The number of the white cards is 8

∵ The total number of the cards is 13

∴ P(white) = 8/13

- Lets find the probability of choosing a black card then a white card

∵ P(black) = 3/7 and P(white) = 8/13

∴ P(black and white) = 3/7 × 8/13 = 24/91

* The probability of choosing a black card then a white card, without

  replacement is 24/91

you should at least use a calculater

step-by-step explanation:

step-by-step explanation:

i hate black