Mathematics, 27.06.2019 07:10 selenaK9514

Solve for (x, y, z), if there is a solution to the given system of linear equations:
x - 3y - 2z = -3
3x + 2y - z = 12
-x - y + 4z = 3
(- 4, 1, 0)
no solution
( 4, 1, 2)
(3, - 4, 2)

Answers: 3

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Solve for (x, y, z), if there is a solution to the given system of linear equations: x - 3y - 2z = -3 3x + 2y - z = 12 -x - y + 4z = 3 (- 4, 1, 0) no solution ( 4, 1, 2) (3, - 4, 2)

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Solve for (x, y, z), if there is a solution to the given system of linear equations:
x - 3y - 2z = -3
3x + 2y - z = 12
-x - y + 4z = 3
(- 4, 1, 0)
no solution
( 4, 1, 2)
(3, - 4, 2)