Which polynomial could be represented by this graph?

Please let me know the choices to better help you.

Step-by-step explanation:

I see zeros at x=-2 , x=0 , x=1 , x=3.

Any time it makes like a little U or upside down U at a zero you are going to have a even power on your factor (for which the zero occurs).  If it goes through the zero increasing or decreasing (not making a kind of U shaped upside down or upside right), it is an odd power.

So at x=-2, (x+2) is going to have an odd power

So at x=0,  (x-0) or (x+0) or even just x is going to have a odd power

So at x=1,  (x-1) is going to have an odd power

So at x=3, (x-3) is going to have an even power

So the polynomial could be represented by

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.