What are the real zeroes of x3 + 6 x2 – 9x - 54?
a. 1,2, 27
b. 3, -3, -6
c. -6,3, -6
d. 2,-1, 18
e. 3,3, -6

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of

Solving

Taking x^2 common from first 2 terms and -9 from last two terms we get

Taking (x+6) common

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

Putting it equal to zero,

So, Option B 3,-3,-6 is correct.

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step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.