What is the completely factored form of d4 − 81?
(d + 3)(d − 3)(d + 3)(d − 3)
(d2 + 9)(d + 3)(d − 3)
(d2 + 9)(d − 3)(d − 3)
(d2 + 9)(d2 − 9)

For this case we must factor the following expression:

Rewriting the expression:

We factor using the formula of the square difference:

Where:

So:

From the second term we have:

Finally, the factored expression is:

homozygous. one is homozygous, while two is heterozygous.

57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465