Part a: solve −np − 80 < 60 for n. show your work. (4 points)
part b: solve 2a − 5d = 30 for d. show your work. (6 points)

Part A ⇒ n>-140/p and p≠0  

Part B. ⇒ d=-30-2a/5

Step-by-step explanation:

Part A. -np-80<60

First, add by 80 both sides of equation.

-np-80+80<60+80

Simplify.

60+80=140

-np<140

Then, multiply by -1 both sides of equation.

(-np)(-1)>140(-1)

Simplify.

np>-140

Divide by p both sides of equation.

np/p>-140/p; p≠0

Simplify to find the answer.

n>-140/p; p≠0 is the correct answer from part a.

Part B. 2a-5d=30

First add by 2a from both sides of equation.

2a-5d+2a=30+2a

Then, simplify.

-5d=30-2a

Divide by -5 from both sides of equation.

-5d/-5=30/-5-2a/5

Simplify, to find the answer.

d=-30-2a/5 is the correct answer from part b.

Part A:

For this case we have the following inequality:

We add 80 to both sides of the inequality:

Dividing between -p on both sides, having to change the inequality sign:

Part B:

For this case we have the following equation:

Subtracting 2a on both sides:

Dividing between -5 on both sides:

the answer is ! ?

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°