Answers: 2
![\bf f(x)=3+e^x(x-5)^3\implies \cfrac{df}{dx}=0+\stackrel{\textit{product rule}}{e^x(x-5)^3+\stackrel{\textit{chain rule}}{e^x\cdot 3(x-5)^2\cdot 1}} \\\\\\ \cfrac{df}{dx}=e^x(x-5)^3+3e^x(x-5)^2\implies \cfrac{df}{dx}=\stackrel{\textit{common factor}}{e^x(x-5)^2[(x-5)+3]} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{df}{dx}=e^x(x-5)^2(x-2)~\hfill](/tpl/images/0329/9129/c7f96.png)
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