Fifteen percent of the pigment in paint color a is black. sixty percent of the pigment in paint color b is black. an unknown amount of paint color b is mixed with 40 ml of paint color a, resulting in a paint that contains 25% black pigment. which equation can be used to solve for x, the total amount of paint in the mixture of the two colors?

a) 0.15(40) + 0.6x = 0.25(40 + x)
b) 0.15(40) + 0.6(x – 40) = 0.25(x)
c) 0.15(40) + 0.6x = 0.25(40 – x)
d) 0.15(40) + 0.6(x + 40) = 0.25(x)

A)  

Step-by-step explanation:

Given : The proportion of pigment in paint color A is black = 0.15

The amount of paint color A= 40 ml

Then , amount of black pigments in paint color A =

Let the unknown amount of paint color B be x.

The proportion of pigment in paint color B is black = 0.6

Then , amount of black pigments in paint color B=

The proportion of pigment in mixture is black = 0.25

Total quantity of mixed color =

Then amount of black pigments in mixture =

Now, the  equation which can be used to solve for x, the total amount of paint in the mixture of the two colors is given by :-

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

what is the answer?