Mathematics, 25.06.2019 06:20 davidgritz2006
What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y=4
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0014/6425/3992b.png)
![\bf \begin{cases} h=3\\ k=5\\ p=1 \end{cases}\implies 4(1)(y-5)=(x-3)^2\implies y-5=\cfrac{1}{4}(x-3)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=\cfrac{1}{4}(x-3)^2+5~\hfill](/tpl/images/0014/6425/e5949.png)
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What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y=4...
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