The perimeter of a rectangle can be found using the equation p = 2l + 2w, where p is the perimeter, l is the length, and w is the width of the rectangle. can the perimeter of the rectangle be 64 units when its width is 11 units and its length is 20 units? a. no. if the length is 20 and the width is 11, the perimeter is p = 20 + 22 = 42, not 64. b. no. if the length is 20 and the width is 11, the perimeter is p = 40 + 22 = 62, not 64. c. yes. if the perimeter is 64 units and the width is 11 units, then p + w is greater than d.40. yes. if the perimeter is 64 units and the width is 11 units, then p + w is less than 40.

B:  No

Step-by-step explanation:

P = 2L + 2W.  If L = 20 and W = 11, then P = 2(20) + 2(11), or 62.  This matches Answer B.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

what is the original number? you forgot to add it.