The sum of three consecutive natural numbers is 156 find the number which is the multiple of 13 out of these numbers

52 is the multiple of 13

Step-by-step explanation:

3x+3=156

3x=153

x=52

52 is the multiple of 13 out of 51 , 52, 53 numbers.

Step-by-step explanation:

Given:  Sum of three consecutive integers 156

To find: Three consecutive integers .

Solution: We have given that

Let first consecutive number  x ,

Second consecutive number=   x+1

Third number =  x+2

According to question :

Sum of three consecutive number

x + x+1 +x+2 = 156 .

Combine like term

3x+3 = 156

On subtracting by 3 both side

3x + 3 -3 = 156 - 3

3x = 153

On dividing by 3

x = 51.

X+1 = 51+1

x+1 = 52.

x +3 = 51+2 = 53.

We can see second number 52 is multiple of 13.

Therefore, 52 is the multiple of 13 out of 51 , 52, 53 numbers.

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do you see a nakes

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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