One leg of a right triangle has length 7 and all sides are whole numbers. find the lengths of the other two sides.

The other 2 sides have lengths 24 and 25.

Step-by-step explanation:

h^2 = x^2 + 7^2 where x is the other leg and h is the hypotenuse.

h^2 - x^2 = 49

(h + x) (h - x) = 49

The factors of 49 are 1 , 7 , and 49.

h + x could be 49 and h - x could be 1:

(25 + 24)(25 - 24) = 49.

So h = 25 and x = 24.

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

the answer is 11.2 (i know i’m late)