Eric wants to sell his car that he paid $7,000 for 3 years ago. the car depreciated, or decreased in value, at a constant rate each month over a 3-year period. if x represents the monthly depreciation amount, which expression shows how much eric can sell his car for today?

a.7,000 − 3x
b.7,000 + 3x
c.7,000 − 36x
d.7,000 + 36x

Option C. 7,000 − 36x

Step-by-step explanation:

Let

y > depreciated value of the car

x---> rate of depreciation

t > the time in months

we know that

The linear equation that represent this situation is

y=7,000-xt

For

t=3 years

Convert to months

t=3*12=36 months

substitute

y=7,000-x(36)

y=7,000-36x

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.