Anzelm wants to burn 540 calories while jogging. jogging burns about 12 calories per minute. when anzelm goes jogging, he usually plans to stop and rest for about 5 minutes. complete the equation below to find the total number of minutes (including rest) that anzelm should plan to be out jogging. use m to represent the total minutes __– =

  12(m -5) = 540

Step-by-step explanation:

The left side of the equation is in the form of a product. A suitable product is ...

  (calories/minute) × (minutes jogging) = (calories burned)

If m represent Anzelm's total minutes, then m-5 will represent the number of minutes actually jogging. This is what goes inside parentheses, so we have ...

  (12 calories per minute) × ((m -5) minutes) = 540 calories

Leaving off the units, which we know are consistent, we have ...

  12 (m -5) = 540

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3