Acoin is tossed 4 times. which of the following represents the probability of the coin landing on heads all 4 times?
a.1/64
b.1/4
c.1/16
d.1/128

C.1/16

Step-by-step explanation:

When a coin is tossed 4 times, the number of outcomes are:

2^4 = 16

So,

From the outcomes, only one outcome will be when there will be all heads

So, the probability will be:

One out of the 16 outcomes

Hence, the probability of a coin landing on heads all 4 times is:

C.1/16

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6