Prove that the line whose intercepts on the axes of x and y. are respectively -2and3 pass through the point 2 and 6

see explanation

Step-by-step explanation:

Using the intercept form of the equation of a straight line

+ = 1

where a is the x- intercept and b the y- intercept

here a = - 2 and b = 3, hence

+ = 1

Multiply through by - 6

3x - 2y = - 6 ← equation in standard form

Substitute x = 2 and y = 6 into the left side of the equation and if equal to the right side then (2, 6) lies on the line

left side = (3 × 2) - 2(6) = 6 - 12 = - 6

Hence line passes through (2, 6)

just sum

10 + 10 = 20