Aright triangle has a hypotensue of length 10 ft and one leg o length 7 ft. how long is the other leg? round the answer to the nearest tenth of a foot.

x = 7.1 to the nearest tenth.

Step-by-step explanation:

Hypotenuse = 10;

Opposite = 7; and

Adjacent = x

Pythagoras rule states that square Hypotenuse side is equal to square Opposite side Plus square Adjacent side, so we solve;

(hyp)² = (opp)² + (adj)². Plug the in:

(10)² = (7)² + (x)²

Evaluate

100 = 49 + x²

subtract 49 from both sides

100 - 49 = 49 - 49 + x²

51 = x²

square root both sides to get rid of the square

√51 = √x², the square cancels the square root

√51 = 7.14

7.14 = x

or x = 7.14 to the nearest tenth.

x = 7.1

                         Check

(10)² = (7)² + (7.14)²

100 = 49 + 50.97 ( approximately = 51)

100 = 49 + 51

100 = 100.

Hope this helps!

the answer is b i just did that

step-by-step explanation:

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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