If δabc ≅ δedf where the coordinates of a(0, 2), b(2, 4), and c(2, −1), what is the measure of df?
a. 3
b. 3.1
c. 5
d. 5.9

C. 5

Step-by-step explanation:

Since Triangle ABC is congruent to EDF it mean that the sides are the same so the length of BC is congruent to the length of DF:

distance formula:

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(2 - 2)^2 + (-1 - 4)^2

d = √(0)^2 + (-5)^2

d = √0 + 25

d = √25

d = 5

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8