If there is no real number solution to the quadratic equation x^2+2x+c=0 what is a possible value of c? 1 -2 0 3

The possible value of 'x' is: 3.

Step-by-step explanation:

A polynomial has no real solutions when the discriminat is less than zero. Given the following polynomial: the discriminant is given by:

In this case, a=1, b=2. By substituting those values:

⇒

Given that the discriminant should be less tha zero, then 'c' must be greater than one.

In this case, the only possible value of 'x' is: 3.

3

Step-by-step explanation:

Given

x² + 2x + c = 0 ← in standard form

with a = 1, b = 2 and c = c

If there are no real solutions then the discriminant

b² - 4ac < 0, that is

2² - (4 × 1 × c ) < 0

4 - 4c < 0 ( subtract 4 from both sides )

- 4c < - 4

Divide both sides by - 4, reversing the sign as a consequence

c > 1

Hence a possible value of c is 3

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."