Find the axis of symmerty for x y=x squared -4x-8

x=2

Step-by-step explanation:

y = x^2 -4x-8

This is in the form y = ax^2 + bx +c

The axis of symmetry, h is found by h=-b/2a

We know a = 1, b=-4

h = -(-4)/ (2*1)

  =4/2

  =2

The axis of symmetry is x=2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

answer: 40.95

step-by-step explanation: