Find the distance from the point to the line. (-1,-2,1); x=4+4t, y=3+t, z=6-t .the distance is typn exact answer, using radicals as needed.)

The distance is  4.726

Step-by-step explanation:

we need to find the distance from the point to the line

Given:- point (-1,-2,1) and line ; x=4+4t, y=3+t, z=6-t .

used formula

Let point P be (-1,-2,1)

using value t=0 and t=1

The point Q (4 , 3, 6) and R ( 8, 4, 5)

Let a be the vector from Q to R :   a = < 8 - 4, 4 - 3, 5 - 6 > = < 4, 1, -1 >

Let b be the vector from Q to P:    b = < -1 - 4, -2 - 3, 1 - 6> = < -5, -5, -5 >

The cross product of a and b is:

= -6i+15j-15k

The distance is :

≈4.726

Therefore, the distance is  4.726

the answer is 18 units because there are 18 small cubes inside the rectangle

hope this and p.s i am also in k12

step-by-step explanation:

its kinda hard to answer this when we dont have all the information that we need.