The equation of line ab is y = 2x + 4. write an equation of a line parallel to line ab in slope-intercept form that contains point (3, −2). (4 points) y = 2x + 4 y = negative 1 over 2 x − 1 over 2 y = − 1 over 2 x − 7 over 2 y = 2x − 8

ANSWER

EXPLANATION

To find the equation of a straight line, we need the slope and a point on that line.

We were given the equation of another line that will help us determine the slope . The given line has equation:

This equation is of the form

where

Since our line of interest is parallel to this line, their slopes are the same.

The line also contains the point (3,-2).

So we substitute the slope and point into the slope-intercept formula:

The required equation is

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3