I am pretty sure it is 3 but I apologize if it is incorrect.
Because the vertex will then be one the x-axis
Where the graph crosses the x axis is where the real zeros exist. The parabola's minimum is at point (-3,-3) by adding a +3 to the right side of the equation will raise the minimum to point (-3,0) therefore giving it only one point where it touches the x axis. Then the parabola will only have one zero, the minimum of the parabola.
The quadratic function
y = -2(x + 2)² - 1
has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)
A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:
y = -2(x + 2)² - 1 + 1 = -2(x + 2)²
which has point (-2, 0) as vertex
Making the outside constant on the right be zero will shift the function so the vertex is on the x-axis. At that point, there is only one real zero.
To make that happen, 3 must be added to the -3 that is there.
The answer is 1 on Edgenuty
the answer is 1
The number is +1
This is the equation of a vertical parabola with vertex at point (-2,-1)
The function has no real zeros
we know that
If the number +1 is added to the equation on the right side
Is a translation one unit up
The vertex of the parabola will be the point (-2,0) and the function will have one real root
see the attached figure to better understand the problem