Suppose the cells of a tumor are idealized as spheres each with a radius of 5 muμm (micrometers). the number of cells has a doubling time of 35 days. approximately how long will it take a single cell to grow into a multi-celled spherical tumor with a volume of 0.8 cm^3 (1 cm=10,000 μm)? assume that the tumor spheres are tightly packed.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: