Match the pairs of polynomials to their products. (xy + 9y + 2) and (xy – 3) x2y2 + 3x2y – 7xy – 27x – 18 (2xy + x + y) and (3xy2 – y) 6x2y3 – 2xy2 + 3x2y2 – xy + 3xy3 – y2 (x – y) and (x + 3y) x3y + 3x2 + 3x2y2 + 7xy – 6 (xy + 3x + 2) and (xy – 9) x2 – 9y2 (x2 + 3xy – 2) and (xy + 3) (x + 3y) and (x – 3y)

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.