Atriangle in the coordinate plane has coordinates of (2,3), (-4,-5), and (-2, 4). it is translated 3 units down. what are its new coordinates? a) (5,3), (-1,-5), (1,4) b) (2,6), (-4,-2), (-2, 7) c) (2,0), (-4,-8), (-2, 1) d) (-1,3), (-7,-5), (-5,4)

 C) (2,0), (-4,-8), (-2, 1)

Step-by-step explanation:

The translation rule for translating a point (x,y) by k units down :-

Given :   A triangle in the coordinate plane has coordinates of (2,3), (-4,-5), and (-2, 4). It is translated 3 units down.

Then, its new coordinates will be :

Hence, the new coordinates =  (2,0), (-4,-8), (-2, 1)

a .4y4

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°