Urgent i can not figure this out ive gotten it wrong 3 times pleae

  see below for a graph

Step-by-step explanation:

Each of the functions:

will only be graphed in the specified domain. You know that ...

  y = -x

is a line with slope -1 through the origin. It won't go through the origin on your graph, because it stops at x = -2. f(x) is not defined as -(-2) at x=-2, so there will be an open circle at the end of this portion of the graph.

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You know that

  y = x+2

is a line with slope +1 through the y-intercept (0, 2). It will only be part of your graph for x-values between -2 and 2, inclusive. Because f(x) is defined as x+2 at the end points of this segment, those points will be shown as solid dots.

__

You know that

  y = 5

is a horizontal line. It will be part of your graph for x > 2, and will have an open circle on the end at x=2. f(2) is not defined as 5, but is defined as 4 (see above), which is why the circle is open.

answer:   y=2x-3

step-by-step explanation:

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: