Given that B has coordinates as (3,7) When reflected about a line the new coordinates are (3,5)
This implies that by reflection x coordinate remains the same but y reduced by 2 units.
Apply the same logic for unknown O.
C is reflected to O.
Original coordinates of C are (5,7)
Hence new coordinates i.e. that of O would be
x coordinate same as 5
y coordinate 2 less = 7-2 = 5
COordinates of O are (5,5)
Answer with explanation:
Coordinates of Point, B is (3,7),and Coordinates of point C is, (6,7).
Now, point B and C are reflected through a line to get , point N and Point O.
While reflection distance of point from Preimage is equal to distance of point from Image.
Line, y=6,is the Line of reflection.
Perpendicular Distance of point , N from Line , y=6 is 1 Unit.
So,Perpendicular, Distance from Point B , to Line, y=6,is equal to 1 Unit.
Similarly, Perpendicular Distance of point , C as well as point O, from Line , y=6 is 1 Unit.
Let , Coordinates of point , N be (x,y) and ,Coordinates of point , O be (p,q).
Joining, BN, Mid point of ,Segment, BN=(3,6)
Mid point of, Segment, CO=(6,6)
Using mid point formula
Coordinates of N=(3,5)
Coordinates of O=(6,5)
it shoild be o
C ) ( 5, 5 )