The area of parking lot is 1710 square meters. a car requires 5 square meters and a bus requires 32 square meters of space. there can be at most 189 vehicles parked at one time. of the cost to park a car is $2.00 and a bus is $6.00, how many buses should be in the lot to maximize income?

To maximize the income should be 28 buses and 160 cars

Step-by-step explanation:

Let

x-----> the number of cars

y ----> the number of bus

we know that

------> inequality A

----> inequality B

The function of the cost to maximize is equal to

Solve the system of inequalities by graphing

The solution is the shaded area

see the attached figure

The vertices of the solution are

(0,0),(0,53),(160,28),(189,0)

Verify

(0,53)

(160,28)

therefore

To maximize the income should be 28 buses and 160 cars

a. -0.3 > -0.33