What is an equation bof the line that is perpendicular to y-4=2(x-6); and passes through the point (-3,-5)

y + 5 = - (x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line.

y - 4 = 2(x - 6) is in this form with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = -

Hence the equation passing through (- 3, - 5) is

y - (- 5) = - (x - (- 3)), that is

y + 5 = - (x + 3) ← equation of perpendicular line

answer: 1 and 3

step-by-step explanation:

0 is its x and y coordinate