Triangle qrs has vertices q(8, –6), r(10, 5), and s(–3, 3). what are the coordinates of the vertices of the image of the triangle after a translation of t–7.6, 4.3(x, y)?

The coordinates of the vertices Q, R, and S of the image of the triangle after a translation are (0.4, -1.7), (2.4, 9.3), and (-10.6, 7.3)

Translation is a way of changing the location of an object on the xy plane.

Given the vertices of the triangle QRS as

Q(8, –6)

R(10, 5)

S(–3, 3)

If the coordinate of the vertices is translated under the rule (x–7.6, y+4.3)

For Q'

Q' = (8-7.6, -6+4.3)

Q' = (0.4, -1.7)

For R':

Q' = (10-7.6, 5+4.3)

Q' = (2.4, 9.3)

For the coordinate S'

S' = (-3-7.6, 3+4.3)

S' = (-10.6, 7.3)

Hence the coordinates of the vertices Q, R, and S of the image of the triangle after a translation are (0.4, -1.7), (2.4, 9.3), and (-10.6, 7.3)

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Q'(0.4,-1.7),R'(2.4,9.3), S'(-10.6,7.3)

Step-by-step explanation:

we know that

The rule of the translation is equal to

(x,y) > (x-7.6,y+4.3)

That means---> the translation is 7.6 units left and 4.3 units up

Find the coordinates of the vertices of the image

Q(8,-6) > Q'(8-7.6,-6+4.3)

Q(8,-6) > Q'(0.4,-1.7)

R(10,5) > R'(10-7.6,5+4.3)

R(10,5) > R'(2.4,9.3)

S(-3,3) > S'(-3-7.6,3+4.3)

S(-3,3) > S'(-10.6,7.3)

the answer is (-4,-4)

hope this ! : d

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.