You want to estimate the proportion of students at your college or university who are employed for 10 or more hours per week while classes are in session. you plan to present your results by a 95% confidence interval. using the guessed value p* = 0.27, find the sample size required if the interval is to have an approximate margin of error of m = 0.03. n =

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

c. 6tan80

step-by-step explanation:

cant see photo

step-by-step explanation: