Write the equation of a line with slope m = 6 and including point (0, 1).

y = 6x + 1

Step-by-step explanation:

linear equations (straight line) are expressed in the following general form:

y = mx + b, where m is the gradient and b is the y-ordinate of the point where the line crosses the y-axis (called the y-intercept)

Given : m = 6

we realize that point (0,1) is actually on the y-axis (i.e x=0), therefore this is coincidentally the y-intercept. Hence b = 1

Therefore the whole equation is

y = 6x + 1

The equation for a line is:

y = mx + c

Note:

y  is the y coordinate

m is the slope

x is the x coordinate

c is the y -intercept (where the line crosses the y-axis.

The question tells us that the slope is 6 (so m is 6)

It also tells that the coordinates are: (0 , 1)    (so x is 0    and y is 1)

Lets plug in these values into the equation and solve to get the missing value ( which is c) :

y = mx + c

1 = 6(0) + c

1 = c.

Now to get the equation of the line, we plug in the values for m and c into y= mx + c:

Equation of line: y = 6x + 1

Equation of line with slop m = 6 and including point (0, 1) is:

y = 6x + 1