The graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (0, 5). what is the solution set of the related equation 0 = ax2 + bx + c?

The equation 0 = ax2 + bx + c has no real roots or no solution.

Step-by-step explanation:

We are told that the graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (0, 5). Since the parabola opens up, the vertex (0, 5) will be the lowest point on the graph of the function. This implies that the parabola does not intersect the x-axis; the line y = 0. Therefore, the equation;

 0 = ax2 + bx + c will have no real roots or no solution. Find the attached.

Here’s the answer. you’re supposed to use 2900 times the interest rate and then add your original amount of money. now you get 2997.15

Ifound this on google “that means that the graph of a function with direct variation has these features: it is a straight line: because the slope is the ratio y/x = k. it passes through the origin (0,0): because y = kx = k (0) = 0.” i hope this you for what your looking for