Atruck can be rented from company a for $40 a day plus $0.30 per mile. company b charges $20 a day plus $0.70 per mile to rent the same truck. find the number of miles in a day at which the rental costs for company a and company b are the same.

50 Miles

Step-by-step explanation:

The equations would be Company A- y=40+0.30x and Company B- y=20+0.70x

When you substitute x for 50 you get A- 40+0.30(50)=40+15=55$ and for B- 20+0.70(50)=20+35=55$ therefor the total miles to be the same for both would be 50 miles.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

its an acute right triangle

step-by-step explanation: